1.

If sodium sulphate is considered to be completely dissociated into cations and anions in aqueous solution, the change in freezing point of water (DeltaT_(f)), when 0.01 mol of sodium sulphate is dissolved in 1 kg of water, is (K_(f)="1.86 K kg mol"^(-1))

Answer»

0.0744 K
0.0186 K
0.0372 K
0.0558 K

Solution :`Na_(2)SO_(4) rarr 2Na^(+)+SO_(4)^(2-)`. Hence, I = 3 (for complete DISSOCIATION)
`DeltaT_(F)=iK_(f)m=3xx1.86xx(0.01)/(1)=0.0588^(@)C`


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