1.

If solutbility of CH_(3) COOAg(s) in a buffer solution of pH equal to 5 is 1.414 xx10^(-y) then calculate the value of y. Given : K_(sp)(CH_(3)COOAg)=10^(-10),K_(a)(CH_(3)COOH)=10^(-5)

Answer»


Solution :`CH_(3)COOAg(s)iffCH_(3)COO^(-)(AQ)+Ag^(+)(aq)`
`CH_(3)COO^(-)(aq)+H_(2)O IFF CH_(3)COOH+OH^(-)`
`{:(x-z,,,,,,,,z,,,10^(-9)):}`
`K_(h)=(10^(-14))/(10^(-5))=(zxx10^(-9))/(x-z)"",""x-z=zimplies z=(x)/(2)`
`K_(sp)=10^(-10)=(x-z)XX x" ",10^(-10)=(x)/(2)xxx`
Solubility `x=sqrt(2)xx10^(-5)`
Solubility `x=1.414xx10^(-y)`
y=5


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