If specific conductivity of N/50 KCl solution at 298 K is 0.002765 ohm – InterviewSolution

1.	If specific conductivity of N/50 KCl solution at 298 K is 0.002765 ohm^(-1)cm^(-1) and resistance of a cell containing this solution is 100 ohms, calculate the cell constant.
Answer» SOLUTION :Cell constant`=("Sp. CONDUCTIVITY")/("Obs. CONDUCTANCE")=`specific conductivity`xx`Obs. RESISTANCE `=0.002765Omega^(-1)cm^(-1)xx100Omega=0.2765cm^(-1)`

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