1.

If `sum_(r=0)^(n) (n)/(""^(n)C_(0))= sum__(r=0)^(n) (n^(2)-3n+3)/(2.""^(n)C_(r))`, thenA. `n = 1`B. `n = 2`C. `n = 3`D. none of these

Answer» Correct Answer - A::C
`underset(r=0)overset(n)sum(r)/(.^(n)C_(r)) = underset(r=0)overset(n)sum(n-r)/(.^(n)C_(n-r))= n/2underset(r=0)overset(n)sum(1)/(.^(n)C_(r))`
`:. n/2 = (n^(2)-3n+3)/(2)`
or `n = 1,3`


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