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If `t a n^2theta=2t a n^2varphi+1`, prove that `cos2theta+s in^2varphi=0.`A. `-1`B. 0C. 1D. none of these. |
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Answer» Correct Answer - B `tan^(2)theta=2tan^(2)phi+1` or `1+tan^(2)theta=2(1+tan^(2)phi)` `rArr sec^(2)theta=2sec^(2)phi` `rArr cos^(2)phi=2cos^(2)phi=1=+cos2theta` `rArr cos 2theta=cos^(2)phi-1=-sin^(2)phi` `rArr sin^(2)phi+cos2theta=0` |
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