1.

If t_(n)= sum_(1)^(n) n, then t_(n)^(1) = sum_(1)^(n) t_(n) =

Answer»

`(N(n+1) )/(2)`
`(n (n+3))/(2)`
`(n (n+1)(n+2) )/( 6)`
`(n (n+4))/(3)`

Answer :C


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