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If `ta n dc`are two complex numbers such that `|t|!=|c|,|t|=1a n dz=(a t+b)//(t-c), z=x+i ydot`Locus of `z`is (where a, b are complex numbers)a. line segment b.straight linec. circled. none of theseA. line segmentB. straight lineC. circleD. none of these |
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Answer» Correct Answer - C `z=(at+b)/(t-c)rArrt=(b+cz)/(z-a)` Now, `|t|=1` `rArr |(b+cz)/(z-a)|=1` `rArr |(z+(b)/(c))/(z-a)|=(1)/(|c|)" " (ne 1" as "|c|ne|t|)` `rArr` locus of z is a circle |
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