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If `tan^(-1)(sqrt(1+x^2-1))/x=4^0`then`x=tan2^0`(b) `x=tan4^0``x=tan1/4^0`(d) `x=tan8^0`A. `x = tan 2^(@)`B. `x = tan 4^(@)`C. `x = tan (1//4)^(@)`D. `x = tan 8^(@)` |
Answer» Correct Answer - D `tan^(-1). (sqrt(1 + x^(2)) -1)/(x) = 4^(@) " " (x != 0)` `rArr (sqrt(1 + x^(2)) -1)/(x) = tan4^(@)` `rArr sqrt(1 + x^(2)) = 1 + x tan 4^(@)` `rArr 1 + x^(2) = 2x tan 4^(@) + 1 + x^(2) tan^(2) 4^(@)` `rArr x = 0 " or " x = (2 tan 4^(@))/(1 - tan^(2) 4^(@)) = tan 8^(@)` Since `x != 0`, we have `x = tan 8^(@)` |
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