1.

If `tan^(-1)x = theta`, find the value of `sin^(-1).(2x)/(1+x^(2))`

Answer» `tan^(-1) x = theta`
`rArr" "x tan = theta`
Now `sin ^(-1).(2x)/(1+x^(2)) = sin ^(-1) .(2tan theta)/(1+ tan^(2)theta)`
`" "= sin ^(-1)(sin 2theta)`
`" " = 2theta`


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