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If `tan^(-1)x = theta`, find the value of `sin^(-1).(2x)/(1+x^(2))` |
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Answer» `tan^(-1) x = theta` `rArr" "x tan = theta` Now `sin ^(-1).(2x)/(1+x^(2)) = sin ^(-1) .(2tan theta)/(1+ tan^(2)theta)` `" "= sin ^(-1)(sin 2theta)` `" " = 2theta` |
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