If `tan^(2) {pi(x+y)}+cot^(2) {pi (x+y)}=1+sqrt((2x)/(1+x^(2)))` where – InterviewSolution

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1.	If `tan^(2) {pi(x+y)}+cot^(2) {pi (x+y)}=1+sqrt((2x)/(1+x^(2)))` where `x, y in R`, then find the least possible value of y.
Answer» Correct Answer - `1//4` `LHS ge 2, RHS le 2` Equality is possible The for `RHS, x=1` For `LHS, tan^(2) pi (1+y)=1` `:. tan^(2) pi y=1` Least value of y ia `1/4`.

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