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If tan A `=a/b`, then find the value of `("a sin A- b cos A")/("a sin A + b cos A")`. |
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Answer» tan A = `a/b` Now `("a sinA-b cosA")/("a sin A+bcosA")=((a sinA)/(cosA)-b)/((a sinA)/(cosA)+b)` (Divide `N^( r)` and `D^(r )` by cos A) `=("a tanA-b")/("a tan A+b")= (a.a/b-b)/(a.a/b+b)` `=((a^(2)-b^(2))/b)/((a^(2)+b^(2))/b)= (a^(2)-b^(2))/(a^(2)+b^(2))`. Ans |
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