If tan (A-B) =1/√3 and cos A=1/2,where A,B are acute angle then find measure of angle B

If tan (A-B) =1/√3 and cos A=1/2,where A,B are acute angle then find

1.	If tan (A-B) =1/√3 and cos A=1/2,where A,B are acute angle then find measure of angle B
Answer» COS A=1/2cos A= cos 60A=60tan (A-B)=1/√3tan (A-B)= TAN 30A-B=3060-B=3060-30=BB=30

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If tan (A-B) =1/√3 and cos A=1/2,where A,B are acute angle then find measure of angle B ​

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If tan (A-B) =1/√3 and cos A=1/2,where A,B are acute angle then find measure of angle B