If tan(A - B) =1/√3 and cos A=1/2where A, B are acute angles. Then find the measure of angle B.

If tan(A - B) =1/√3 and cos A=1/2where A, B are acute angles. Then

1.	If tan(A - B) =1/√3 and cos A=1/2where A, B are acute angles. Then find the measure of angle B.
Answer» 1/2COS A= COS 60A=60TAN (A - B) =1/√3TAN (A - B) = TAN 30A-B=3060-B=30B=60-30=30

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If tan(A - B) =1/√3 and cos A=1/2where A, B are acute angles. Then find the measure of angle B.​

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If tan(A - B) =1/√3 and cos A=1/2where A, B are acute angles. Then find the measure of angle B.