1.

If tan (A + B) = p and tan (A – B) = q, then write the value of tan 2B.

Answer»

tan (x - y) = \(\frac{tanx-tany}{1+tanxtany}\)

tan[(A + B) - (A - B)] = \(\frac{tan(A+B)-tan(A-B)}{1+tan(A-B)tan(A+B)}\)

tan (2B) = \(\frac{p-q}{1+pq}\)



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