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If tan (A + B) = p and tan (A – B) = q, then write the value of tan 2B. |
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Answer» tan (x - y) = \(\frac{tanx-tany}{1+tanxtany}\) tan[(A + B) - (A - B)] = \(\frac{tan(A+B)-tan(A-B)}{1+tan(A-B)tan(A+B)}\) tan (2B) = \(\frac{p-q}{1+pq}\) |
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