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If tan (A + B) = $\sqrt{3}$ and tan (A-B) = $\frac{1}{\sqrt{3}}$ , $\angle A +\angle B$ < $90^{0}$ ,$A\geq B$ ,then $\angle A $ is1). $90^{0}$2). $30^{0}$3). $45^{0}$4). $60^{0}$ |
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