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If `tan a theta-tan b theta=0`, then prove that the values of `theta` forms an A.P. |
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Answer» We have `tan a theta = tan b theta` `rArr a theta = n pi + b theta, n in Z` `rArr (a -b) theta = n pi` `rArr n pi//(a -b) = theta` Thus, the values of `theta` form an A.P. with common difference `pi//(a -b)` |
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