If tanA=1/2,cotB=3 then A+B=?

1.	If tanA=1/2,cotB=3 then A+B=?
Answer» 45°Step-by-step EXPLANATION:tanA=1/2 and TANB = 1/3tan(A+B) = (tanA+tanB)/(1-tamAtanB) TAN(A+B)= (1/2+1/3)/[1-(1/2)(1/3)]= (5/6)/(5/6) =1 tan(A+B) = tan45°So, A+B= 45°

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If tanA=1/2,cotB=3 then A+B=?​

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