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If tanA=4 then find sinA cosA |
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Answer» HELLO EVERYONE YOUR ANSWER IS GIVEN BELOW : given : tanA = 4 find : SINACOSA =? now, we use identity - 1+tan²A=sec²A 1+(4) ²=sec²A 1+16=sec²A 17=sec²A secA=√17 cosA=1/√17 now, sin²A+cos²A=1 sin²A=1-cos²A sin²A=1-(1/√17) ² sin²A=1-1/17 sin²A=16/17 sinA=4/√17 sinA.cosA=4/√17 . 1/√17 sinA.cosA=4/17. THANK YOU☺. I HOPE IT'S HELPFUL FOR YOU.
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