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If tanθ + sinθ = m and tanθ – sinθ = n, then prove that m2 – n2 = 4sinθ tanθ |
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Answer» We have, tanθ + sinθ = m ...... (i) And tanθ -sinθ = n .......... (ii) Now, m + n = 2 tanθ And m – n = 2 sinθ. (m + n)(m -n) = 4 sinθtanθ m2 -n2 = 4 sinθtanθ |
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