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if `tantheta=(4)/(3)`, then the value of `(3sintheta+2costheta)/(3sintheta-2costheta)` isA. 0.5B. `-0.5`C. `3.0`D. `-3.0` |
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Answer» Correct Answer - c `(3sintheta+2costheta)/(3sintheta-2costheta)` divide numerator `&` denominator by `cos theta` `=(3(sintheta)/(costheta)+(2costheta)/(costheta))/((3sintheta)/(cos theta)-(2cos theta)/(cos theta))[(sintheta)/(costheta)=tantheta]` `=(3tantheta+2)/(3 tan theta-2)` Put value of `tan theta` `=(3xx(4)/(3)+2)/(3xx(4)/(3)-2)=(6)/(2)=3` |
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