1.

if `tantheta=(4)/(3)`, then the value of `(3sintheta+2costheta)/(3sintheta-2costheta)` isA. 0.5B. `-0.5`C. `3.0`D. `-3.0`

Answer» Correct Answer - c
`(3sintheta+2costheta)/(3sintheta-2costheta)`
divide numerator `&` denominator by `cos theta`
`=(3(sintheta)/(costheta)+(2costheta)/(costheta))/((3sintheta)/(cos theta)-(2cos theta)/(cos theta))[(sintheta)/(costheta)=tantheta]`
`=(3tantheta+2)/(3 tan theta-2)`
Put value of `tan theta`
`=(3xx(4)/(3)+2)/(3xx(4)/(3)-2)=(6)/(2)=3`


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