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If `tantheta+cottheta=5` then `tan^(2)theta+cot^(2)theta` isA. 23B. 24C. 25D. 26 |
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Answer» Correct Answer - a Given `tan theta+cot thea=5` `rArrtantheta+cot theta=5` `rArr[tan theta+cottheta]^(2)=5^(2)` (squaring both sides) `rArrtan^(2)theta+cot^(2)theta+2tan thetacottheta=25` `rArrtan^(2)theta+cot^(2)theta=25-2[because tan theta . cot theta=1]` ` rArr tan^(2)theta+cot^(2)theta=23` |
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