1.

If te solubility product of BaSO_(4) is 1.5 xx 10^(-9) in water, its solubility in moles per litre, is

Answer»

`1.5 xx 10^(-9)`
`3.9 xx 10^(-5)`
`7.5 xx 10^(-5)`
`1.5 xx 10^(-5)`

SOLUTION :`BaSO_(4) hArr BA^(2+) + SO_(4)^(--)`
Solubility constant `= S xx S`
`1.5 xx 10^(-19) = S^(2), S = sqrt(1.5 xx 10^(-19)), S = 3.9 xx 10^(-5)`.


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