If temperature of black body increases from `300K` to `900K`, then the rate of energy radiation increases byA. 81B. 3C. 9D. 2

If temperature of black body increases from `300K` to `900K`, then the

1.	If temperature of black body increases from `300K` to `900K`, then the rate of energy radiation increases byA. 81B. 3C. 9D. 2
Answer» Correct Answer - A We can write , `((T_(2))/T_(1))^(4)=(E_(2))/(E_(1))` `(E_(2))/(E_(1))=((900)/(300))^(4)rArr(E_(2))/(E_(1))=(3)^(4)` , `E_(2)=81E_(1)rArr(E_(2))/(E_(1))=81`

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If temperature of black body increases from `300K` to `900K`, then the rate of energy radiation increases byA. 81B. 3C. 9D. 2

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