1.

If the 0.05 molar solution of M^(+) is replaced by a 0.0025 molar M^(+) solution, then the magnitude of the cell potential would be

Answer»

35 mV
70 mV
140 mV
700 mV

Solution :From the above EQUATION,
`(2.303RT)/(F)"LOG(1)/(0.05)=70mV`
`=70xx10^(-3)V=0.07V`
`therefore(2.303RT)/(F)(1.301)=0.07`
or `(2.303RT)/(F)=(0.07)/(1.301)=0.0538`
For the NEW concentration,
`E_(CELL)=(2.303RT)/(F)"log"(1)/(0.0025)`
`=0.0538log400=0.0538xx2.6021`
`=0.140V=140mV`


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