If the activation energy for the forward reaction is 150 "kJ mol"^(-1) – InterviewSolution

1.	If the activation energy for the forward reaction is 150 "kJ mol"^(-1)and that of the reverse reaction is 260 "kJ mol"^(-1), what is the enthalpy change for the reaction ?
Answer» 410 `"kJ mol"^(-1)` `-110" kJ mol"^(-1)` `110" kJ mol"^(-1)` `-410" kJ mol"^(-1)` SOLUTION :(b) : `DeltaH=E_(f)-E_(b)=150-260" kJ"=-110" kJ"`

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