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If the amount of heat given to a system is 40 J and the amount of work done on the system is 15 J then the change in internal energy isA. 50 JB. `-50J`C. `30J`D. `55J` |
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Answer» Correct Answer - D `dQ=du+domega` `du=dQ-(domega)` `=40+15=55J`. |
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