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If the angle between `2hati+ 2hatj- hatk` and vector `hati + chatk` is acute, then the maximum value of c is : |
Answer» Correct Answer - 2 `cos theta = (vecA.vecB)/(|vecA||vecB|) =- ((2hati + 2hatj + hatk ) xx (hati + chatk))/(sqrt((2)^(2) + (2)^(2) + (-1)^(2) .sqrt(1+ c^(2))))` `= (2-c)/(3sqrt(1 + c^(2)))` If `theta` is acute , ` cos theta` is positive. `" "cos theta ge 0` `" "2cge 0` `" "2 le c` `" "c le 2` Thus, the maximum value of c is 2. |
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