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If the angle between the transmission axis of the polarizer and the analyser is 45^@ what will be the ratio of intensities of the incident light and the transmitted light for the analyser? |
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Answer» SOLUTION :`I=I_0cos^2theta=I_0(COS45)^2=I_0xx(1/sqrt2)^2=I_0/2` `I_0/I=2` |
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