If the angle between the vectors vec(A) and vec(B) is theta, the value of the product (vec(B)xxvec(A)).vec(A) is equal to:

If the angle between the vectors vec(A) and vec(B) is theta, the value

1.	If the angle between the vectors vec(A) and vec(B) is theta, the value of the product (vec(B)xxvec(A)).vec(A) is equal to:
Answer» `BA^(2)sintheta` `BA^(2)COSTHETA` `BA^(2)SINTHETACOSTHETA` zero Solution :Here `vec(C )=(vec(B)xxvec(A))=BAsintheta`then `vec(c ).vec(A)=(Basintheta)Acos90^@`=zero

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If the angle between the vectors vec(A) and vec(B) is theta, the value of the product (vec(B)xxvec(A)).vec(A) is equal to:

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