If the angles of a quadrilateral are x°, (x – 20)°, (x – 30)° a

1.	If the angles of a quadrilateral are x°, (x – 20)°, (x – 30)° and (x + 10)° find x.
Answer» Sum of ANGLES of quadrilateral is 360 DEGREE. X°+ (x – 20)°+(x – 30)° + (x + 10)°= 360° x°+x – 20°+x – 30° + x + 10°= 360° x°+x°+x°+x°– 20°– 30°+ 10°= 360° 4x°-40=360° 4x°= 360°+40°=400° x=400/4°=100° The angles = x°=100°, (x – 20)°=100-20°=80°, x – 30°=100-30=70°, x + 10°= 100+10°=110° ANSWER.

If the angles of a quadrilateral are x°, (x – 20)°, (x – 30)° and (x + 10)° find x.

Answer»

Sum of ANGLES of quadrilateral is 360 DEGREE.

X°+ (x – 20)°+(x – 30)° + (x + 10)°= 360°

x°+x – 20°+x – 30° + x + 10°= 360°

x°+x°+x°+x°– 20°– 30°+ 10°= 360°

4x°-40=360°

4x°= 360°+40°=400°

x=400/4°=100°

The angles = x°=100°, (x – 20)°=100-20°=80°,

x – 30°=100-30=70°, x + 10°= 100+10°=110° ANSWER.