1.

If the angular momentum of an electron is vecj then the magnitude of the magnetic moment will be

Answer»

eJ2m
`(2m)/(eJ)`
`(eJ)/(2m)`
`(eJ)/m`

Solution :The MAGNETIC moment of an electron revolving in a circular ORBIT of RADIUS r is `M = 1/2` …..(i)
and its angular MOMENTUM,
`J = I OMEGA = mr^(2) xx v/r = mvr` ….(ii)
From (i) and (ii), we get,
`therefore` M/J = 1/2 (evr)/(mvr)=1/2 e/m implies M = (eJ)/(2m)`


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