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If the area of a triangle with vertices `(-3,0),(3,0)` and `(0,0` is 9 sq. units. Then the value of `k` will beA. 3B. 6C. 9D. 12 |
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Answer» Correct Answer - A Let the vertices of the `Delta ABC` be `A(-3, 0), B(3, 0)` and `C (0, k)`. `:.` Area of `Delta ABC=1/2 |(,,),(,,),(,,)|` Given, area is 9 `implies 9=1/2 {-3(-k)+1(3k)}` `implies 18=3k+3k` `implies k=18/6=3` |
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