1.

If the area of circle increases at a uniform rate, then prove that theperimeter varies inversely as the radius.

Answer» Area of a circle, `A = pir^2`
`:. (dA)/dt = 2pir (dr)/dt`
It is given that area of circle increases at uniform rate.
`:. (dA)/dt = k`, where `k` is a constant.
`=> 2pir (dr)/dt = k`
`=> (dr)/dt = k/(2pir)`
Now, perimeter of the circle `P = 2pir`
`:. (dP)/dt = 2pi(dr)/dt`
`=> (dP)/dt = (2pi)(k/(2pir)) = k/r`
Thus, rate of change of perimeter varies inversely with the radius.


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