1.

A ladder 13m long leans against a wall. The foot of the ladder ispulled along the ground away from the wall, at the rate of 1.5m/sec. How fastis the angle `theta`betweenthe ladder and the ground is changing when the foot of the ladder is 12m awayfrom the wall.

Answer» `tan theta = y/x`
`sin theta = y/13`
differentiating wrt t
`cos theta* (d theta)/dt = ((dy)/dt)/13`
`12/13*(d theta)/dt = (dy/dt)/13`
`(d theta)/dt = (dy/dt)/12` eqn (1)
now, `x^2 + y^2 = 13^2`
`2xdy/dt + 2ydy/dt = 0`
`2*12*1.5 = -2*5*dy/dt`
`dy/dt = 24*1.5/-10= 36/-10`
putting in eqn (1)
`(d theta)/dt = -36/(10*12) = -0.3`rad/sec


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