1.

If the arithmetic mean of the distribution is 38.2 and median is 41.6 then what will be the most likely value of the mode?

Answer»

\((\overline X - Z ) = 3 (\overline X - M)\)

Z = 3M – 2 \(\overline X\)

Z= (3 × 41.6 ) – (2 × 38.2)

= 124.8 – 76.4

= 48.4



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