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If the arithmetic mean of the distribution is 38.2 and median is 41.6 then what will be the most likely value of the mode? |
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Answer» \((\overline X - Z ) = 3 (\overline X - M)\) Z = 3M – 2 \(\overline X\) Z= (3 × 41.6 ) – (2 × 38.2) = 124.8 – 76.4 = 48.4 |
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