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If the bar magnet in exercise 5.13 is turned around by 180^@, where will the new null points be located? |
Answer» Solution :When BAR MAGNET given in above example is turned around by 180° such that its poles get interchanged, we obtain new null points `N_1 and N_2` on the equator of bar magnet in the plane of figure, suppose at distance y from the centre of magnet. See the figure given below.  At null points `N_1 and N_2`, we have `THEREFORE (mu_0)/( 4 pi) ((m) /( y^3) )= (mu_0)/( 4pi) ((2m)/( r^3))""`[From equation (1) of above example] `therefore y^(3)= (r^3)/( 2)` `therefore y= (r)/( 2^(1//3)) ` `therefore y= (14)/( 1.2599) = 11.112` CM Note : Here all the points located on the circle of radius y in the equatiorial plane of a bar magnet are ALSO null points along with points `N_(1) and N_(2)`. |
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