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If the binding energy of the electron in a hydrogen atom is `13.6 eV`, the energy required to remove the electron from the first excited state of `Li^(++)` isA. `30.6 eV`B. `13.6 eV`C. `3.4 eV`D. `122.4 eV` |
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Answer» Correct Answer - A Energy required to remove an electron from an orbit is `+ (13.6(Z)^(2))/n^(2) eV` So, to remove the electron from the first excited state of `Li^(2+)` is `E=(+13.6xx3^(2))/2^(2)=3.4xx9= +30.6 eV` |
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