If the binding energy per nucleon of deuterium is 1.115 MeV, its mass defect in atomic mass unit is

If the binding energy per nucleon of deuterium is 1.115 MeV, its mass

1.	If the binding energy per nucleon of deuterium is 1.115 MeV, its mass defect in atomic mass unit is
Answer» 0.0048 0.0024 0.0012 0.0006 Solution :BINDING energy per NUCLEON is `E_"bn"=E_b/A` For DEUTERIUM , A=2 `therefore ` 1.115 MeV=`E_b/2` or `E_b=2xx1.115` MeV or `E_b=DeltaMc^2` Mass defect, `DeltaM=(2xx1.115 )/931.5 U "" [because 1 u = 931.5 MeV//c^2]` =0.0024 u

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If the binding energy per nucleon of deuterium is 1.115 MeV, its mass defect in atomic mass unit is

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