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If the bisector of the vertical angle of a triangle bisects the base , prove that triangle is an isosceles |
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Answer» Answer: That's your answer dude Step-by-step explanation: GIVEN △ABC, AD is a bisector of ∠A which meets base BC at D such that BD=DC. Produce AD to meet E such that AD=ED. Now, in △ABD and △DEC BD=DC ...... [Given] AD=DE ........ [By CONSTRUCTION] ∠ADB=∠EDC ..... [Vertically opposite angles] ∴ △ABD≅△EDC [∵SAS congruence ] ⟹AB=EC and ∠BAD=∠DEC ..... [CPCT] ALSO, ∠BAD=∠DAC ⟹∠DAC=∠DEC ⟹ In △ACE, ∠AEC=∠CAE ⟹AC=CE ........ [SIDES opposite to equal angles] ⟹AB=AC Hence, △ABC is isosceles |
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