1.

If the bond dissociation energies of XY, X_(2) and Y_(2) (all diatomic molecules) are in the ratio of 1 : 1 : 0.5 and Delta_(f) H for the formation of XY is - 200 kJ " mole"^(-1). The bond dissociation energy of X_(2) will be

Answer»

100 KJ `mol^(-1)`
800 kJ `mol^(-1)`
300 kJ `mol^(-1)`
400 kJ `mol^(-1)`

SOLUTION :`XYrarrX_((g))+Y_((g)), DeltaH=+"a kJ/mole"^(-1)".........(i)"`
`X_(2)rarr2X, DeltaH=+" a kJ/mole.....(ii)"`
`Y_(2)rarr2Y, DeltaH=+0.5" a kJ/mole.......(III)"`
`(1)/(2)XX(ii)+(1)/(2)xx(iii)-(i)`, gives
`(1)/(2)X_(2)+(1)/(2)Y_(2)rarrXY,`
`DeltaH=(+(a)/(2)+(0.5)/(2)a-a)"kJ/mole"`
`+(a)/(2)+(0.5a)/(2)-a=-200`
a = 800


Discussion

No Comment Found

Related InterviewSolutions