1.

If the bond dissociation energy of XY, x_ (2) ANDy_(2) (all diatomic molecules) are in the ratio of 1 : 1 : 0.5 and Delta_(f)H for the formation of XY is - 200 kJ mol^(-1). The bond dissociation energy of X_(2) will be :

Answer»

`100 kJ MOL^(-1)`
`200 kJ mol^(-1)`
`800 kJ mol^(-1)`
`400 kJ mol^(-1)`

Solution :Let the BOND dissociation energies of XY, `X_(2) and Y_(2)` be x, x and `0.5 x kJ mol^(-1)` respectively.
`(1)/(2) X_(2) + (1)/(2) Y_(2) RARR XY Delta H_(f) = - 200 kJ mol^(-1)`
`Delta H = (1)/(2) Delta H (X_(2)) + (1)/(2) Delta H (Y_(2)) - Delta H (XY) - 200 = (1)/(2) x + (0.5 x)/(2) - x` or `- 0.25 x = - 200`
`x = (200)/(0.25) = 800 kJ mol^(-1)`


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