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If the charge on capacitor is increased by 5C, the energy stored in the capacitor is increased by 21%, what will be initial charge on the capacitor ? |
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Answer» 10 C `U = (1)/(2) (Q^(2))/(C)` If charge BECOME Q + 5 then energy U. = 1.21 U `:. U = (1.21U)/(1)` `:. (1)/(2) ((Q+5)^(2))/(C) = 1.21 xx(1)/(2) (Q^(2))/(C)` `:. (Q+5)^(2) = 1.21 Q^(2)` `:. Q +5 =1.1 Q ` `:. 5 =0.1 Q :. = 50 C ` |
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