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If the circuit is connected to a 110 V, 12 kHz supply? Hence, explain the statement that a capacitor is a conductor at very high frequencies. Compare this behaviour with that of a capacitor in a dc circuit after the steady state. |
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Answer» Solution :(a) `I_(0)=3.88A` (b) `phi=0.2` and is NEARLY ZERO at high frequency. THUS, at high frequency, C acts LIKE a conductor. For a dc circuit, after STEADY state, `omega=0` and C amounts to an open circuit. |
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