1.

If the concentration of glucose (C_(6)H_(12)O_(6)) in blood is 0.9 g L^(-1), what will be the molarity of glucose in blood?

Answer»

5 M
50 M
0.005 M
0.5 M

Solution :Molar MASS of GLUCOSE `(C_(6)H_(12)O_(6))=72+12+96=180" g mol"^(-1)`
`"Molaarity"=("conc. in g L"^(-1))/("Molar mass")=(0.90gL^(-1))/("180 g mol"^(-1))=0.005M.`


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