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If the concentration of lead iodide in its saturated solution at 25^(@)C be 2 xx 10^(-3) moles per litre, then the solubility product is |
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Answer» `4 xx 10^(-6)` `K_(sp) = 4S^(3) = 4 xx [2 xx 10^(-3)]^(3) = 32 xx 10^(-9)`. |
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