1.

If the concentration of OH^(-) ions in the reaction Fe(OH)_(3)(s)hArr Fe^(3+)(aq)+3OH^(-)(aq)is decreased by 1/4 times, then equilibrium concentration of Fe^(3+) will increase by

Answer»

8 times
16 times
64 times
4 times

Solution :`Fe(OH)_(3)(s)hArr Fe^(3+)(AQ)+3OH^(-)(aq)`
`K=[Fe^(3+)][OH^(-)]^(3)`
Concentration of `OH^(-)` ion in the REACTION is decreased by 1/4 times, then equilibrium concentration of `Fe^(3+)` will be increased by `(4)^(3)=-64` times in order to keep the value of K to be CONSTANT.


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