If the current I is 2mA then find the temperature at which diode operates. The cut-in voltage of diode is 0.6V. The reverse saturation current of diode is 10^-9A. Resistance R is 1.3KΩ.(a) 45.85°C(b) 50.47°C(c) 60.26°C(d) 56.89°CThe question was posed to me in class test.This interesting question is from Characteristic Equation of Diode-2 topic in portion Diode Circuit of Analog Circuits

If the current I is 2mA then find the temperature at which diode opera

1.	If the current I is 2mA then find the temperature at which diode operates. The cut-in voltage of diode is 0.6V. The reverse saturation current of diode is 10^-9A. Resistance R is 1.3KΩ.(a) 45.85°C(b) 50.47°C(c) 60.26°C(d) 56.89°CThe question was posed to me in class test.This interesting question is from Characteristic Equation of Diode-2 topic in portion Diode Circuit of Analog Circuits
Answer» Right answer is (a) 45.85°C The EXPLANATION is: EQUATION for diode current where I0 = reverse saturation current η = ideality factor VT = thermal voltage V = APPLIED voltage Since in this QUESTION ideality factor is not mentioned it can be taken as one. VD = 3-(2mAx1.3k) = 0.4V VT = T/11600 Thus Temperature, T = 11600×0.0275 = 319 Kelvin = 45.85°C.

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