1.

If the current in an `AC` circuit is represented by the equation, `i=5sin(300t-pi/4)` Here `t` is in second and in an ampere, calculate (a) peak and rms value of current (b) frequecne of `AC` (c) average current.

Answer» i) Comparing the given equation with general equation, we have
`I= I_(0)sin(omegat+-phi)`
`therefore` The peak value, `I_(0)`=5A
and `I_(rms) = I_(0)/sqrt(2)= 5/sqrt(2) = 3.535`A
ii) Angular frequency,
`omega = 300 rads^(-1)`
`therefore` `v= omega/(2pi) = 300/(2pi) ~~ 47.75 Hz`
iii) Average current, `I_(av) = (2/pi)I_(0) = (2/pi)(5) = 3.18`A


Discussion

No Comment Found

Related InterviewSolutions