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If the current through a solenoid changes with time electromagnetic induction takes place in the solenoid. This is known as self-induction. In general, for a current I, the induced emf in the coil is e=-L(dI)/(dt). L is the self-inductance of the solenoid. On the other hand, such change in the current in a solenoid can produce electromagnetic induction in another adjacent solenoid. The induced emf in the other solenoid e=-M(dI)/(dt), M is called the mutual inductance of the solenoids. If L_(1) and L_(2) are the self-inductance of the adjacent coils then their mutual inductance M=ksqrt(L_(1)L_(2)). If the magnetic flux produced by the current in one coil is totally linked with the other coil then k = 1. Self-inductance (in H) of the coil in question (III) is |
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Answer» 0.1 |
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