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| 1. |
If the current through a solenoid changes with time electromagnetic induction takes place in the solenoid. This is known as self-induction. In general, for a current I, the induced emf in the coil is `e=-L(dI)/(dt)`. L is the self-inductance of the solenoid. On the other hand, such change in the current in a solenoid can produce electromagnetic induction in another adjacent solenoid. The induced emf in the other solenoid `e=-M(dI)/(dt)`, M is called the mutual inductance of the solenoids. If `L_(1)` and `L_(2)` are the self-inductance of the adjacent coils then their mutual inductance `M=ksqrt(L_(1)L_(2))`. If the magnetic flux produced by the current in one coil is totally linked with the other coil then k = 1. Self-inductance (in H) of the coil in question (III) isA. 0.1B. 0.08C. 0.01D. 0.008 |
| Answer» Correct Answer - D | |